4/3a^2-3=7/2a

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Solution for 4/3a^2-3=7/2a equation: 


a in (-oo:+oo)

(4/3)*a^2-3 = (7/2)*a // - (7/2)*a

(4/3)*a^2-((7/2)*a)-3 = 0

(4/3)*a^2+(-7/2)*a-3 = 0

4/3*a^2-7/2*a-3 = 0

DELTA = (-7/2)^2-(-3*4/3*4)

DELTA = 113/4

DELTA > 0

a = ((113/4)^(1/2)+7/2)/(4/3*2) or a = (7/2-(113/4)^(1/2))/(4/3*2)

a = 3/8*((113/4)^(1/2)+7/2) or a = 3/8*(7/2-(113/4)^(1/2))

a in { 3/8*(7/2-(113/4)^(1/2)), 3/8*((113/4)^(1/2)+7/2) }

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